64Digits

22222

Posted by Bryan on Nov. 26, 2007, 4:07 p.m.

yay

Comments

Bryan 16 years, 5 months ago

Fail, you have to use 5 2's.

TwistyWristy 16 years, 5 months ago

22 / 2 = ll

TwistyWristy

Bryan 16 years, 5 months ago

((2-2)+22)/2 = 11

2*2*2+2+2 = 12

s 16 years, 5 months ago

2=2=2=2=2

Bryan 16 years, 5 months ago

That would be 0 >_>

Bryan 16 years, 5 months ago

13, Can't solve this one, anyone?

2*2*2*2-2 = 14

2^(2+2)-2/2 = 15

2^(2+2)-2+2 = 16

Juju 16 years, 5 months ago

(22 + 2 + 2) / 2 = 13

frenchcon1 16 years, 5 months ago

2 + 22 / 22 = 3

Juju 16 years, 5 months ago

(2+2)^2 + (2/2) = 17

((2+(2/2))^2)*2 = 18

frenchcon1 16 years, 5 months ago

2 + 2 + 2 = 6 / 2 = 3 - 2 = 1

2 * 2 = 4 + 2 = 6 - 2 = 4 - 2 = 2

2 * 2 = 4 * 2 = 8 - 2 = 6 / 2 = 3

2 + 2 + 2 + 2 = 8 / 2 = 4

2 * 2 = 4 * 2 = 8 + 2 = 10 / 2 = 5

2 * 2 = 4 * 2 = 8 / 2 = 4 + 2 = 6

2 * 2 = 4 * 2 = 8 - (2 / 2) = 7

2 * 2 = 4 * 2 = 8 + 2 = 10 - 2 = 8

2 * 2 = 4 * 2 = 8 + (2 / 2) = 9

2 + 2 + 2 + 2 + 2 = 10

((2-2)+22)/2 = 11

2*2*2+2+2 = 12

(22 + 2 + 2) / 2 = 13

2*2*2*2-2 = 14

2^(2+2)-2/2 = 15

~~2^(2+2)-2+2~~(2+2+2+2)*2 = 16

(2+2)^2 + (2/2) = 17

((2+(2/2))^2)*2 = 18